• what is the maximum height reached by the rocket? A model rocket is launched straight upward with an initial speed of 48.3 m/s. It accelerates with a constant upward acceleration of 2.23 m/s^2 until its engines stop at an altitude of 160 m. The acceleration of gravity is 9.81 m/s^2.

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• Cd= 1.5 because the rocket uses a true domed parachute. v = 5 m/s I'm increasing v because this rocket's going pretty high and I don't want it to take forever to come down. This is the equivalent to a four-foot drop (ouch). D = sqrt( (8 m g) / (prCdv2) ) = sqrt( (8*3.6*9.81) / (3.14*1.22*1.5*52) ) = 1.4 m.

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• What is the maximum height that Alice will reach? So, to find out how high she will jump, Alice needs to find a local maximum of the function $$\text{bounce}(t)$$. One way to do this is using calculus. Let's find out how. We'll start out with another example, and come back to Alice later. Example

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• Mar 17, 2020 · The time taken by the body to reach the maximum height is called the time of ascent. Let v 0 = Velocity of projection and θ = Angle of projection. Resolving v 0 into two components viz. v 0 Cosθ the horizontal component. And v 0 Sinθ the vertical component. Consider vertical Component v 0 Sinθ. Due to this component, there is the vertical motion of the body.

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• The Flight of a Rocket A rocket is fired from the ground with an initial velocity of 160 feet per second. If the rocket does not have a parachute: A) When is the rocket 400 feet high? B) When will the rocket hit the ground? C) How can you show that 400 feet is the maximum height reached by the rocket? 1.

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• Jan 28, 2014 · A rocket, initially at rest on the ground, accelerates straight upward from rest with constant acceleration 49.0m/s2 . The acceleration period lasts for time 7.00s until the fuel is exhausted. After that, the rocket is in free fall. Find the maximum height ymax reached by the rocket. Ignore air resistance and assume a constant acceleration due to gravity equal to 9.80 m/s2 .

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A rocket was launched directly upwards from rest. Its motors operated for 30 s after it left the launch pad, providing it with a constant vertical acceleration of 6.0 ms^{-2} during this time. It's motors then switched off. (a) Calculate it's velocity and its height above the launch pad when its motors are switched off. Ok I have its velocity as 180ms^{-1} and the height as 2.7km (b) Calculate ...= average weight of rocket v m = maximum velocity during motor burn Finally we can calculate some ideal values for our rocket. Given the picture of our rocket in Figure 2, lets figure out our altitude at burnout and our maximum altitude theoretically. Using my kids' Alpha rocket with an A8-3 motor in-stalled, it weighs 38.8 grams at lift off.

Line of sight calculation is based on earth radius and height above ground of transmitter (and receiver). R = 21000000 (21 million feet) approximately. Based on plane trigonometry, d squared = h * (2 * R + h). This is distance to horizon for an observer at height h above surface of radius R.
• My class recently done a water rocket project. Now we have to do a report and i need to calculate the maximum height of our rocket with the use of a inclinometer. At lanch day the angle was 60 and the distance from the person and tyhe lanching pad was 20m. also the height of the person measuring is 5'5.

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• Velocity is the speed the rocket is traveling. This is determined at any given point by taking the velocity at the previous point and applying the acceleration at the current point. (For rockets that stay in the lower atmosphere, max Q occurs at maximum velocity.) Altitude is the height above ground reached by the rocket.

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• The objective of this growth utility program is to predict a measure of a child's biological maturity. Peak height velocity (PHV) is a somatic biological maturity indicator and reflects the maximum velocity in statural growth during adolescence.

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• Maximum height = ..... m (2) (iv) Figure 2 shows four velocity−time graphs. Taking air resistance into account, which graph, A, B, C or D, shows how the velocity of the rocket changes as it falls from the maximum height it reached until it just hits the ground? Write the correct answer in the box. (1)

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• Jun 12, 2014 · An "A" engine has a maximum impulse of 2.5 Newton-seconds, a "1/2A" has 1.25 N-sec, a "B" has 5.0 N-sec, a "C" has 10.0 N-sec, and a "D" has 20.0 N-sec. If we compare the curves for B6 and the C6, we find that both engines have the same average thrust (6 Newtons), but the "C" engine burns almost twice as long for double the total impulse.

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• A rocket is launched perpendicularly with an initial acceleration of 10 m/s 2, if the fuel runs out after 1 minute, what will be the maximum height reached by the rocket? homework-and-exercises newtonian-mechanics rocket-science

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• A model rocket, weight 0.50Ibf is launched vertically from level ground. The thrust of its motor is T=3.0Ibf and lasts for 2.4secs. After the motor shuts down, the rocket behaves as a ballistic projectile, reaching maximum height and then crashing to the ground . a & b) Calculate the height and the velocity of the rocket when the motor stops.

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Math homework help video on optimizing the height that a rocket can fly. Instructions on finding the maximum height of a rocket fired into the air by identifying key features of a quadratic equation. Problem 1. Jul 11, 2013 · Using the equations, calculate the initial velocity (v o) and the maximum height (s ) of the rocket launch. Then repeat the calculations for each of the launches. Remember to enter your results in the data table following each launch. If a toy rocket is launched with an initial velocity of 128 feet per second, then its height h after t seconds is given by the equation, h(t) = ­16t2 + 128t. How long will it take the toy rocket to get to the highest point? The height (h) in feet of a ball t seconds after being dropped A rocket, initially at rest on the ground, accelerates straight upward with a constant acceleration of 34.3 m/s^2. The rocket accelerates for a period of 10.0 s before exhausting its fuel. The rocket continues its ascent until its motion is halted by gravity. The rocket then enters free fall. Find the maximum height, ymax, reached by the rocket.

The Flight of a Rocket A rocket is fired from the ground with an initial velocity of 160 feet per second. If the rocket does not have a parachute: A) When is the rocket 400 feet high? B) When will the rocket hit the ground? C) How can you show that 400 feet is the maximum height reached by the rocket? 1.
• Q. If a toy rocket is launched vertically upward from ground level with an initial velocity of 128 feet per second, then its height h after t seconds is given by the equation h(t) = -16t 2 +128t (if air resistance is neglected). When will the object reach its maximum height?

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velocity of 128 feet per second, then its height h after t seconds is given by the equation, h(t) = ­16t2 + 128t. How long will it take the toy rocket to get to the highest point? The height (h) in feet of a ball t seconds after being dropped is given by function, h(t) = ­16t2 + 9. How long will it take for Mar 28, 2020 · The maximum height of a projectile is calculated with the equation h = vy^2/2g, where g is the gravitational acceleration on Earth, 9.81 meters per second, h is the maximum height and vy is the vertical component of the projectile's velocity. If the angle of launch or the velocity of the projectile are not known, these quantities can be derived. Derive the original velocity and angle if not given these quantities. How long did it take the rocket to reach its maximum height aft er the engine cut out? c. Estimate the time the rocket was in free fall before it reached the earth. 7. Use the table and graph in Item 5. a. Use a graphing calculator to determine a quadratic h(t) function for the data. b. Sketch the graph of the function on the grid in Item 5. 8. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the maximum height reached by the rocket, to the nearest tenth of a foot. y=-16x^2+160x+150 Answers: 3At liftoff, both the boosters and the main engines are operating. The three main engines together provide almost 1.2 million pounds of thrust and the two solid rocket boosters provide a total of 6,600,000 pounds of thrust. The total thrust at launch is about 7.8 million pounds. 4 seconds – assuming no rocket. force or air resistance. The acceleration due to gravity is the same in both directions, slowing down on the way up, speeding up on the way back down.

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Calculation of time t₃ it takes for the rocket to return to ground level from its maximum altitude: h = ½ * (– g) * t²₃ h = ½ * (– g) * t²₃ h = -½ * g * t²₃ 158.1632653061226 = -½ * 9.8 * t²₃ Assume that the rocket travels to a small enough height that the Earth’s gravitational force can be considered constant. (a) What are the speed and height, in terms of g and t, when the rocket’s fuel runs out? (b) What is the maximum height the rocket reaches in terms of g and t? (c) If t = 30.0s, calculate the rocket’s maximum height. Jan 28, 2014 · A rocket, initially at rest on the ground, accelerates straight upward from rest with constant acceleration 49.0m/s2 . The acceleration period lasts for time 7.00s until the fuel is exhausted. After that, the rocket is in free fall. Find the maximum height ymax reached by the rocket. Ignore air resistance and assume a constant acceleration due to gravity equal to 9.80 m/s2 . The maximum height of the object is the highest vertical position along its trajectory. The maximum height of the projectile depends on the initial velocity v 0, the launch angle θ, and the acceleration due to gravity. The unit of maximum height is meters (m). H = maximum height (m) v 0 = initial velocity (m/s) g = acceleration due to gravity ...

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the maximum velocity that can be reached (a) With a single-stage rocket. umax ≃ 4,905 m/s (b) With a two-stage rocket. Assume that the structural coeﬃcient ε and the payload ratio λ are identical for both stages. umax ≃ 6,160 m/s Problem R.9Consider a liquid-propellant rocket engine operating steadily at high altitude (i.e. pa ≃ 0 ... Mar 16, 2018 · On September 15, 2017, North Korea launched a Hwasong-12 IRBM on a standard (i.e., not lofted) trajectory, apparently to demonstrate that it could reach the American island territory of Guam. The missile reached a maximum altitude of 770 km and splashed down 3700 km from its launch site. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the maximum height reached by the rocket, to the nearest tenth of a foot. y=-16x^2+160x+150 Answers: 3Blast a car out of a cannon, and challenge yourself to hit a target! Learn about projectile motion by firing various objects. Set parameters such as angle, initial speed, and mass. Explore vector representations, and add air resistance to investigate the factors that influence drag. 1. The height of a rocket above the ground is modelled by the quadratic function ℎ (\)=−4\5+32\, where ℎ\) is the height in metres \ seconds after the rocket was launched. a) How long will the rocket be in the air? How do you know? b) How high will the rocket be after 3 seconds? c) What is the maximum height that the rocket will reach? 2. How long did it take the rocket to reach its maximum height aft er the engine cut out? c. Estimate the time the rocket was in free fall before it reached the earth. 7. Use the table and graph in Item 5. a. Use a graphing calculator to determine a quadratic h(t) function for the data. b. Sketch the graph of the function on the grid in Item 5. 8.

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Hi there! Doing a little final practice and was asked to find the max height and the time of the max height of the rocket. I can't figure out the code for the time.Hi there! Doing a little final practice and was asked to find the max height and the time of the max height of the rocket. I can't figure out the code for the time.b) The maximum height reached c) -At what height on its upward journey the bullet had a velocity of 100m.s 1 Example 3: A man standing on a rooftop 30m high throws a squash ball vertically upwards at 50m.s-1. Calculate: a) The maximum height reached b) The time taken to reach the maximum height c) The total time taken to hit the ground The K class motor that will power this rocket produces an average thrust of 190 lb., and has a total impulse of 418 lbf-sec. Estimate the maximum altitude for the rocket, as well as maximum velocity, burnout velocity, and time to apogee. First, determine the motor burn time and the average rocket mass: t = I/F = 418/190 = 2.2 sec.

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(a) The rocket was launched from a height of 180 feet (b) The maximum height of the rocket occurred 3 seconds after launch (c) The rocket was in the air approximately 6 seconds before hitting the ground (d) The rocket was above 300 feet for approximately 2 seconds. Maximum height = ..... m (2) (iv) Figure 2 shows four velocity−time graphs. Taking air resistance into account, which graph, A, B, C or D, shows how the velocity of the rocket changes as it falls from the maximum height it reached until it just hits the ground? Write the correct answer in the box. (1) Excel was used to calculate the performance of the rocket from the motor chart values, the calculated drag coefficient, and the weight of the rocket. S b =38.56 meters, and S c =89.6 meters for a total altitude of 128.2 meters or 423 feet. on the graph to determine the rock’s maximum height. 5. How much kinetic energy should the rock be launched with to reach a maximum distance of: i. 3R e ii. 6R e 6. With what velocity should the rock be launched to reach a maximum distance of 4R e? 7. Complete the chart again, but now the rock has an initial velocity of 1.2 x 104 m/s. 8.

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